Javascript does not have a built in method for parsing a url (to get the individual parts that make up a url). Here is a link to a great little function that does all you need, called parseURI.
It uses regex to quickly break apart a url into source, protocol, authority, userInfo, user , password, host, port, relative, path, directory, file, query, and anchor.
Here are few examples:
var myUrl = "http://www.test.com/testdir/testfile.htm?q=test"; //get the host name of a url alert( parseUri(myUrl).host ); //get the query string of a url alert( parseUri(myUrl).query ); //get the path of the url alert( parseUri(myUrl).path );
Here is a copy of the Steven Levithan’s code:
/* parseUri 1.2.1 (c) 2007 Steven Levithan <stevenlevithan.com> MIT License */ function parseUri (str) { var o = parseUri.options, m = o.parser[o.strictMode ? "strict" : "loose"].exec(str), uri = {}, i = 14; while (i--) uri[o.key[i]] = m[i] || ""; uri[o.q.name] = {}; uri[o.key[12]].replace(o.q.parser, function ($0, $1, $2) { if ($1) uri[o.q.name][$1] = $2; }); return uri; }; parseUri.options = { strictMode: false, key: ["source","protocol","authority","userInfo","user","password","host","port","relative","path","directory","file","query","anchor"], q: { name: "queryKey", parser: /(?:^|&)([^&=]*)=?([^&]*)/g }, parser: { strict: /^(?:([^:\/?#]+):)?(?:\/\/((?:(([^:@]*):?([^:@]*))?@)?([^:\/?#]*)(?::(\d*))?))?((((?:[^?#\/]*\/)*)([^?#]*))(?:\?([^#]*))?(?:#(.*))?)/, loose: /^(?:(?![^:@]+:[^:@\/]*@)([^:\/?#.]+):)?(?:\/\/)?((?:(([^:@]*):?([^:@]*))?@)?([^:\/?#]*)(?::(\d*))?)(((\/(?:[^?#](?![^?#\/]*\.[^?#\/.]+(?:[?#]|$)))*\/?)?([^?#\/]*))(?:\?([^#]*))?(?:#(.*))?)/ } };
Sun, Jun 28, 2009
Tech Tips